1. apa yang kalian
ketahui tentang invers pada matriks
JIka A dan B matriks bujur sangkar sedemikian rupa sehingga
A B = B A = I , maka B disebut balikan atau invers dari A dan dapat dituliskan
( B sama dengan invers A ). Matriks B juga mempunyai invers yaitu A maka
dapat dituliskan . Jika tidak ditemukan matriks B, maka A dikatakan matriks
tunggal (singular). Jika matriks B dan C adalah invers dari A maka B = C.
Matriks A = dapat di-invers apabila ad - bc ≠ 0
Matriks A = dapat di-invers apabila ad - bc ≠ 0
2. sebutkan syarat"
invers pada matriks
1. Jika | A | = 0, maka
matriks A tidak mempunyai invers. Oleh karena itu,
dikatakan matriks A sebagai matriks singular.
2. Jika | A | <> 0,
maka matriks A mempunyai invers. Oleh karena itu,
dikatakan matriks A sebagai matriks nonsingular.
dikatakan matriks A sebagai matriks nonsingular.
3. berikan contoh matriks invers
Matriks
A =
dan B = 


AB = 
=
= I (matriks identitas)



BA = 
=
= I (matriks identitas)



Maka dapat dituliskan bahwa
(B Merupakan invers dari A)

Contoh 2:
Matriks
A =
dan B = 


AB = 
= 



BA = 
= 



Karena AB ≠ BA ≠ I maka matriks A dan
matriks B disebut matriks tunggal.
Contoh 3:
Matriks
A = 

Tentukan Nilai dari A-1
Jawab:

Contoh 4:
Matriks
A =
, B =
, AB = 



Dengan menggunakan rumus, maka didapatkan



Maka



Ini membuktikan bahwa 

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